hopefully for youHmm maybe. Then perhaps both would be right...?
hopefully for youHmm maybe. Then perhaps both would be right...?
haha im the sameyou know what i hate, coming on BOD and reading everyones answers. Then seeing i got questions wrong. It just makes me more depressed..
the answer was 17.8for 28c i dived how far he could see out to sea somehting like 4.5k by how high his eyes where. like 1.6 that equalled 2.8 then i times that by 16 or however high it was and bingo there is your answer...... i hope, i did do in no joke like 5seconds
Well if I've shown all the working out to the answer (which I did) they are looking for I'll get the marks.hopefully for you
You mean 1.6/4.5^2the answer was 17.8
using the equation h = k d^2
k = 4.5^2/1.6
lol me to... but i can't seem to stay awayyou know what i hate, coming on BOD and reading everyones answers. Then seeing i got questions wrong. It just makes me more depressed..
yes my mistakeYou mean 1.6/4.5^2
I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.also. the last question was in my opinion the hardest. i said juan was correct, because there were 8 differences between the theoretical probability and the first experiment, where as there were only 4 differences between the theoretically probable answer and experiment two... what did everyone else get, and what were your explanations?
you cant simplify dat any furtherfuckkk i didnt fully simplify 25a . - still get one mark if i wrote -2x - 9 ?
The question was difference between two dice, not what the value of the dice was.I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
I think the question was talking about the difference between the numbers rolled on the dice e.g. if 4 and 5 were rolled the difference is 1I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
thats what i said, because from the sample space there were 36 possible outcomes and of which the 6 different differences were possible 6 times. eg 6/36 - 1/6. they all had equal chances of occuringI said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
DUDDE sorry but ur rongI said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
that's how i did it. i didn't have time to write soem examples of the theoretical probability though. hopefully i would still get 3 marks for that though because i have an answer and the other parts to the question.I don't think i did very will in the test. byebye uni! :[I think the question was talking about the difference between the numbers rolled on the dice e.g. if 4 and 5 were rolled the difference is 1
i think you had to draw one of those tables with like 1-6 across the top and 1-6 down the side. then fill in what the difference's would be in the middle.
if that's right then exp 2 was closest to the theoretical probability
that is exactly what i doneThere was a 6/36 chance of getting a difference of 0, 10/36 for 1, 8/36 for 2, 6/36 for 3, 4/36 for 4, 2/36 for 5. You just multiply these chances with 18 to get the difference they should theoretically show. So experiment two was more correct..
haha yer don't worry about it, you should be sweet.that's how i did it. i didn't have time to write soem examples of the theoretical probability though. hopefully i would still get 3 marks for that though because i have an answer and the other parts to the question.I don't think i did very will in the test. byebye uni! :[
FUCKKK YESSS. are you right tho. please say yes lmaoQUESTION 27c
3 raffles - 100 tickets each
MARY: 2/100 = 1/50 = 0.02 <B>(1 mark)</B>
JANE:
Propability of winning both ticks is 1/100 x 1/100 = 1/10,000 <B>(1 mark)</B>
Probabilty of winning first draw but not the second = 1/100 x 99/100 = 99/10,000
Propability of winning second but not first = 99/100 x 1/100 = 99/10,000
CONCLUSION...
Propability of winning AT LEAST 1 (is the sum of the above 3 calculations)
1/10 000 plus 99/10 000 plus 99/10 000 = 199/10 000 = 0.0199 <B>(1 mark)</B>
Hence, mary has a slightly beter chance... <B>(1 mark)</B>