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Section II (1 Viewer)

knel

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for 28c i dived how far he could see out to sea somehting like 4.5k by how high his eyes where. like 1.6 that equalled 2.8 then i times that by 16 or however high it was and bingo there is your answer...... i hope, i did do in no joke like 5seconds
 

matttayl

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for 28c i dived how far he could see out to sea somehting like 4.5k by how high his eyes where. like 1.6 that equalled 2.8 then i times that by 16 or however high it was and bingo there is your answer...... i hope, i did do in no joke like 5seconds
the answer was 17.8

using the equation h = k d^2

k = 4.5^2/1.6
 

I Study Hard

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also. the last question was in my opinion the hardest. i said juan was correct, because there were 8 differences between the theoretical probability and the first experiment, where as there were only 4 differences between the theoretically probable answer and experiment two... what did everyone else get, and what were your explanations?
I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
 

mystiques4

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I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
The question was difference between two dice, not what the value of the dice was.
 

emma211

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I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
I think the question was talking about the difference between the numbers rolled on the dice e.g. if 4 and 5 were rolled the difference is 1

i think you had to draw one of those tables with like 1-6 across the top and 1-6 down the side. then fill in what the difference's would be in the middle.

if that's right then exp 2 was closest to the theoretical probability
 

matttayl

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I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
thats what i said, because from the sample space there were 36 possible outcomes and of which the 6 different differences were possible 6 times. eg 6/36 - 1/6. they all had equal chances of occuring
 

Question?

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I said that since the chance of rolling any one face on the dice was 1/6 that if the dice were rolled 18 times then theoretically each number should have come up 3 times, and therefor he was wrong, because experiment 1 was closer to the expected result.
DUDDE sorry but ur rong
 
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There was a 6/36 chance of getting a difference of 0, 10/36 for 1, 8/36 for 2, 6/36 for 3, 4/36 for 4, 2/36 for 5. You just multiply these chances with 18 to get the difference they should theoretically show. So experiment two was more correct..
 

tegan-leanne

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I think the question was talking about the difference between the numbers rolled on the dice e.g. if 4 and 5 were rolled the difference is 1

i think you had to draw one of those tables with like 1-6 across the top and 1-6 down the side. then fill in what the difference's would be in the middle.

if that's right then exp 2 was closest to the theoretical probability
that's how i did it. i didn't have time to write soem examples of the theoretical probability though. hopefully i would still get 3 marks for that though because i have an answer and the other parts to the question.I don't think i did very will in the test. byebye uni! :[
 

Question?

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There was a 6/36 chance of getting a difference of 0, 10/36 for 1, 8/36 for 2, 6/36 for 3, 4/36 for 4, 2/36 for 5. You just multiply these chances with 18 to get the difference they should theoretically show. So experiment two was more correct..
that is exactly what i done
 

emma211

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that's how i did it. i didn't have time to write soem examples of the theoretical probability though. hopefully i would still get 3 marks for that though because i have an answer and the other parts to the question.I don't think i did very will in the test. byebye uni! :[
haha yer don't worry about it, you should be sweet.
 

cmanassa

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QUESTION 27c

3 raffles - 100 tickets each

MARY: 2/100 = 1/50 = 0.02 <B>(1 mark)</B>

JANE:
Propability of winning both ticks is 1/100 x 1/100 = 1/10,000 <B>(1 mark)</B>
Probabilty of winning first draw but not the second = 1/100 x 99/100 = 99/10,000
Propability of winning second but not first = 99/100 x 1/100 = 99/10,000

CONCLUSION...
Propability of winning AT LEAST 1 (is the sum of the above 3 calculations)
1/10 000 plus 99/10 000 plus 99/10 000 = 199/10 000 = 0.0199 <B>(1 mark)</B>

Hence, mary has a slightly beter chance... <B>(1 mark)</B>
 

Question?

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QUESTION 27c

3 raffles - 100 tickets each

MARY: 2/100 = 1/50 = 0.02 <B>(1 mark)</B>

JANE:
Propability of winning both ticks is 1/100 x 1/100 = 1/10,000 <B>(1 mark)</B>
Probabilty of winning first draw but not the second = 1/100 x 99/100 = 99/10,000
Propability of winning second but not first = 99/100 x 1/100 = 99/10,000

CONCLUSION...
Propability of winning AT LEAST 1 (is the sum of the above 3 calculations)
1/10 000 plus 99/10 000 plus 99/10 000 = 199/10 000 = 0.0199 <B>(1 mark)</B>

Hence, mary has a slightly beter chance... <B>(1 mark)</B>
FUCKKK YESSS. are you right tho. please say yes lmao
 

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