Predictions for Chemistry 2014 HSC? (1 Viewer)

Jim Moriarty

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I think we'll get a good calculation question this year.

Try this one:

The solubility of highly soluble, thermally unstable salts such as ammonium chloride may be determined by back titration.

In one experiment a 5.00 mL saturated solution of ammonium chloride, NH4Cl, at 20oC,
was diluted with distilled water to 250.0 mL in a standard flask.

A 20.0 mL aliquot of this solution was added to 10.0 mL of 0.400 M NaOH solution.
The solution was heated to drive off the ammonia formed by this reaction.

When the flask had cooled, the excess hydroxide ions were neutralised by 14.7 mL of 0.125 M HCl solution. The molar mass of ammonium chloride is 53.5 g/mol.

(i) Write an equation for the neutralisation reaction.
(ii) Determine the amount, in mole, of NaOH that was originally added to the ammonium chloride solution.
(iii) Determine the amount, in mole, of ammonium chloride in the 20.0 mL aliquot.
(iv) Calculate the amount, in mole, of ammonium chloride in 5.00 mL of the saturated solution.
(v) Calculate the solubility, in g/L, of ammonium chloride in water at 20oC.

7 marker, 1 + 1 + 2 + 1 + 2

This was from the 2012 VCE Chemistry Paper for those interested.
 

enigma_1

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mreditor16

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I have a bad feeling someone is going to get infracted or banned due to this derailing. Be careful guys :/
 
Joined
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I think we'll get a good calculation question this year.

Try this one:

The solubility of highly soluble, thermally unstable salts such as ammonium chloride may be determined by back titration.

In one experiment a 5.00 mL saturated solution of ammonium chloride, NH4Cl, at 20oC,
was diluted with distilled water to 250.0 mL in a standard flask.

A 20.0 mL aliquot of this solution was added to 10.0 mL of 0.400 M NaOH solution.
The solution was heated to drive off the ammonia formed by this reaction.

When the flask had cooled, the excess hydroxide ions were neutralised by 14.7 mL of 0.125 M HCl solution. The molar mass of ammonium chloride is 53.5 g/mol.

(i) Write an equation for the neutralisation reaction.
(ii) Determine the amount, in mole, of NaOH that was originally added to the ammonium chloride solution.
(iii) Determine the amount, in mole, of ammonium chloride in the 20.0 mL aliquot.
(iv) Calculate the amount, in mole, of ammonium chloride in 5.00 mL of the saturated solution.
(v) Calculate the solubility, in g/L, of ammonium chloride in water at 20oC.

7 marker, 1 + 1 + 2 + 1 + 2

This was from the 2012 VCE Chemistry Paper for those interested.
 
Joined
Feb 16, 2014
Messages
2,258
Gender
Male
HSC
2014
I think we'll get a good calculation question this year.

Try this one:

The solubility of highly soluble, thermally unstable salts such as ammonium chloride may be determined by back titration.

In one experiment a 5.00 mL saturated solution of ammonium chloride, NH4Cl, at 20oC,
was diluted with distilled water to 250.0 mL in a standard flask.

A 20.0 mL aliquot of this solution was added to 10.0 mL of 0.400 M NaOH solution.
The solution was heated to drive off the ammonia formed by this reaction.

When the flask had cooled, the excess hydroxide ions were neutralised by 14.7 mL of 0.125 M HCl solution. The molar mass of ammonium chloride is 53.5 g/mol.

(i) Write an equation for the neutralisation reaction.
(ii) Determine the amount, in mole, of NaOH that was originally added to the ammonium chloride solution.
(iii) Determine the amount, in mole, of ammonium chloride in the 20.0 mL aliquot.
(iv) Calculate the amount, in mole, of ammonium chloride in 5.00 mL of the saturated solution.
(v) Calculate the solubility, in g/L, of ammonium chloride in water at 20oC.

7 marker, 1 + 1 + 2 + 1 + 2

This was from the 2012 VCE Chemistry Paper for those interested.
Are you sure iii and iv is mol? I have this feeling its concentration.
 

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