Physics Predictions/Thoughts (1 Viewer)

[abelsj01]

What did everyone get for 30bi and ii?

0 for i since it won't conduct a current and whatever the emf was from 0.0-0.03s

 

[abelsj01]

What would a 70 raw be?

probs a high band 4

 

[Rattlehead15]

0 for i since it won't conduct a current and whatever the emf was from 0.0-0.03s

For the second one I put emf = and put in all of the variables but ran out of time before I could put it in my calculator will I still get 1 mark?

 

[matiaschong123]

0 for i since it won't conduct a current and whatever the emf was from 0.0-0.03s

But for ii , it asked for the max emf in the ring with the incomplete flux linkage , so wouldn’t it just be 0???

 

[Jamesssss10]

probs a high band 4

Damn hopefully clutch a band 5 with the last few mc guesses

 

[Rattlehead15]

can some explain 16, and isn't 10 B because field is parallel

For 10 its D because the force on XY is the same all the way round because its a 2D side always perpendicular to the field. Q16 I guessed D and got it right

 

[abelsj01]

But for ii , it asked for the max emf in the ring with the incomplete flux linkage , so wouldn’t it just be 0???

i was banking on them not asking a trick question so i didnt put zero but flux is independent of current anyways so there would be an emf induced

 

[Alamjot]

What would a 70 raw be?

it will be similar to last years

 

[Cathode_RT]

it will be similar to last years

doubt it, definetily harder that last year, so scaling will be decent

 

[ExtremelyBoredUser]

How did everyone go?

 

[matiaschong123]

i was banking on them not asking a trick question so i didnt put zero but flux is independent of current anyways so there would be an emf induced

i won’t lie i’m not 100% sure but ig we will find out , i thought it was just a trick question ngl

 

[Alamjot]

For 10 its D because the force on XY is the same all the way round because its a 2D side always perpendicular to the field. Q16 I guessed D and got it right

fml

 

[Jamesssss10]

What was 23 b, did you just do E=hc/lambda and minus the wavelengths on the denominator?

 

[Rattlehead15]

What was 23 b, did you just do E=hc/lambda and minus the wavelengths on the denominator?

I just put in whatever the lower of the two given wavelengths was, I dont remember the question so I may have done it wrong but thats what I remember doing

 

[Jamesssss10]

My answer was a wavelength

I just put in whatever the lower of the two given wavelengths was, I dont remember the question so I may have done it wrong but thats what I remember doing

yh I didn’t like that q

 

[jackarana]

I just put in whatever the lower of the two given wavelengths was, I dont remember the question so I may have done it wrong but thats what I remember doing

don't you just convert max wavelength to frequency and then convert to energy

 

[Rattlehead15]

don't you just convert max wavelength to frequency and then convert to energy

Yes but I did E = hc/lambda instead of converting to freq

 

[jackarana]

Yes but I did E = hc/lambda instead of converting to freq

are both correct?

 

[carrotsss]

Bruh is our universe constantly expanding rn? For q20 because I picked A because hubbles law

The question wasn’t asking that though

 

[Rattlehead15]

are both correct?

Yeah because its the same thing just two different ways