-insert title here-
- Jun 19, 2014
- Outside reality
The direction in which you resolve the forces is not horizontal/vertical. It is parallel/perpendicular to the inclined surface. This is because the net force of the object is parallel to the inclined surface.Hi, can someone explain to me why it's N=mg cos theta and not mg=N cos theta for Q14a(i)? and also why is it suddenly sin theta for a(ii)?
This is for extension 2 paper btw, thanks!