General Thoughts: Mathematics (1 Viewer)

[cheeseoid]

were they playing a set amount of games? for that iii) i got 0.99999 or 1 LOL

My friend told me (in language i will never understand) that because there are 2 players and not just 1, there is a way to calculate it using a series.

 

[NFmusic1995]

I integrated to get f(x) = 2x^2-3x+C. I solved that simultaneously with y=5x-7, since they intersect and formed the equation of 2x^2-8x+(C-7) = 0. I then used the discriminant = 0 to find C and got f(x)=2x^2-3x+1.

i got +4 at the end for C

 

[titaniumwithin]

Made an account just to rage at this question...

For the Q16 fish question,

Trout Population was = 375-e^0.04t

that means initial trout population (at t=0) was 375-e^0

or 374, right?

its just 1 mark in the many that i cannot possibly got, but why the heck would bos do something as stupid as a kaizo trap in here??

That's what I did.

 

[dunjaaa]

It wasn't a difficult exam, just longer then the usual. 96 raw hopefully, but I screwed the volume question since I took the positive root 'y', also for absolute value one I accidentally wrote 0<m<=2 rather than m>=2 derp. Last part of last question took years to get out. The carp and trout question, you had to absolute the rate at which the trout were decreasing otherwise you'll get a negative log. Other then that it was pretty good exam overall, just waiting for extension 1 on thursday did 90% prep for it and 10% prep for 2u.

 

[mathsiam]

Made an account just to rage at this question...

For the Q16 fish question,

Trout Population was = 375-e^0.04t

that means initial trout population (at t=0) was 375-e^0

or 374, right?

its just 1 mark in the many that i cannot possibly got, but why the heck would bos do something as stupid as a kaizo trap in here??

That's what i got too!! I was worried it was some trick question o.o

 

[leesh95]

were they playing a set amount of games? for that iii) i got 0.99999 or 1 LOL

I got 1? but IDK how that was possible since wouldn't that mean that only one guy would win? or both of them win?

 

[joe_y]

Can someone please upload the paper so i can post my responses ! easy exam

 

[Plaguesbread]

It wasn't a difficult exam, just longer then the usual. 96 raw hopefully, but I screwed the volume question since I took the positive root 'y', also for absolute value one I accidentally wrote 0<x<=2 rather than x>=2 derp. Last part of last question took years to get out. The carp and trout question, you had to absolute the rate at which the trout were decreasing otherwise you'll get a negative log. Other then that it was pretty good exam overall, just waiting for extension 1 on thursday did 90% prep for it and 10% prep for 2u.

yeah man, im thinking if thats 2u, and the last couple of years for 3u was easy (especially last year, very easy) - 3U IS GOING TO BE A FUCKING NIGHTMARE!

 

[leesh95]

My friend told me (in language i will never understand) that because there are 2 players and not just 1, there is a way to calculate it using a series.

But there was a question just like that in 1992 hsc I think and it was also in the Cambridge textbook and you solved it using series.

 

[arabesque]

is it just me or was it really hard :'(

 

[ocatal]

My friend told me (in language i will never understand) that because there are 2 players and not just 1, there is a way to calculate it using a series.

You are meant to make a series, find the common ratio and then calculate the limiting sum.

 

[spanky125]

If it asked for exact value and I gave both the decimal and the exact will I still get the marks?

 

[titaniumwithin]

yeah man, im thinking if thats 2u, and the last couple of years for 3u was easy (especially last year, very easy) - 3U IS GOING TO BE A FUCKING NIGHTMARE!

If 3u was written by the same person. Those who are doing it are going to get screwed.

 

[bedpotato]

My friend told me (in language i will never understand) that because there are 2 players and not just 1, there is a way to calculate it using a series.

Yeah, I used a series and got 1/11...

 

[YuMaNuMa]

I integrated to get f(x) = 2x^2-3x+C. I solved that simultaneously with y=5x-7, since they intersect and formed the equation of 2x^2-8x+(C-7) = 0. I then used the discriminant = 0 to find C and got f(x)=2x^2-3x+1.

Used another method but got the same answer. I found the gradient of the tangent and worked it out from there.

TBH, okayish exam but so many fucking silly mistakes. The log question got me as well - hope they'll be gentle and give me 2/3

 

[dunjaaa]

I did a limiting sum, so Pat can win on his 1st, 2nd 3rd,... role. 1/36 + (35/36)^2(1/36) + (35/36)^4(1/36) + .... Factorise 1/36 out and you should get 1/36{1 + (35/36)^2 + (35/36)^4 +....). Sum to infinity, 1/36{1/(1-(35/36)^2)} = 36/71

 

[mac1996]

did u guys get 60 something for the minimum distance between the cars?

 

[andybandy]

definatley know i got that probability question wrong

 

[Shazer2]

i got +4 at the end for C

But b^2 - 4ac, so (-8)^2 - 4(2)(C+7) = 64 - 8C - 56. So -8C = -8, C = 1?

 

[sammie293]

i got +4 at the end for C

me too..Is 4 right?