First Year Mathematics B (Integration, Series, Discrete Maths & Modelling) (1 Viewer)

RenegadeMx

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Re: MATH1231/1241/1251 SOS Thread

How did this happen. The guy goes "and here's the trick" and writes the result. How can he just look at that LHS and do what he did? What's the trick I'm missing?

differentiate top wrt x and u get those terms out, once u understand that in future DE's u can get ur int factor and skip a few steps
 

leehuan

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Re: MATH1231/1241/1251 SOS Thread











The question
Why does {v1, v2} still form a spanning set for R3 again?
 

InteGrand

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Re: MATH1231/1241/1251 SOS Thread











The question
Why does {v1, v2} still form a spanning set for R3 again?
It doesn't. We need at least three vectors to span R3.

 
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leehuan

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Re: MATH1231/1241/1251 SOS Thread

Oh my fault on that one. Should've stated to not assume v1 and v2 were scalar multiples of each other.

I've lost bits of my question then. I'll need to find an example, sec
 

leehuan

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Re: MATH1231/1241/1251 SOS Thread

Never mind, sorry I know what i did. It was asking for a basis for a span, not R3

Question types like this were what I was alluding to. Capture.PNG
 

Flop21

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Re: MATH1231/1241/1251 SOS Thread

Why can't you just multiply top and bottom by x (bringing the top x out of the integral), thus cancelling the x on the top, and then do the tan sub? Rather than what they do? (obviously you get different answers tho)

 

He-Mann

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Re: MATH1231/1241/1251 SOS Thread

Why can't you just multiply top and bottom by x (bringing the top x out of the integral), thus cancelling the x on the top, and then do the tan sub? Rather than what they do? (obviously you get different answers tho)

I see no useful consequence of multiplying top and bottom by x. Also, you cannot bring the x out of the integral because it's a variable and not a constant.

Multiplying top and bottom by x



does nothing. Their method is already efficient. Doing integration by substitution is what you want to avoid.
 
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Flop21

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Re: MATH1231/1241/1251 SOS Thread

I see no useful consequence of multiplying top and bottom by x. Also, you cannot bring the x out of the integral because it's a variable and not a constant.

Multiplying top and bottom by x



does nothing. Their method is already efficient. Doing integration by substitution is what you want to avoid.
oh thanks
 

Paradoxica

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Re: MATH1231/1241/1251 SOS Thread

What's actually happening though in the second line? Why/how does he put a (x+1) -1?
Add 0, multiply by 1. That's a key principle in algebraic manipulation. The trick is knowing the exact expression for 0 and 1, which only comes from experience or intuition.
 

RenegadeMx

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Re: MATH1231/1241/1251 SOS Thread

What's actually happening though in the second line? Why/how does he put a (x+1) -1?
splits up the fraction which when u integrate gives ur ln and arctan term
 

He-Mann

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Re: MATH1231/1241/1251 SOS Thread

What's actually happening though in the second line? Why/how does he put a (x+1) -1?
The third line explains why he does it. How he saw this is a result of foresight gain from experience/intuition as Paradoxica described.

Here's some insights:

1) The fraction is polynomial of degree 1 divided by polynomial of degree 2. When you have this (degree of numerator is one less than degree of denominator), then you think of a logarithms.

2) The denominator is sum of two squares, think of tan.
 

RenegadeMx

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Re: MATH1231/1241/1251 SOS Thread

The third line explains why he does it. How he saw this is a result of foresight gain from experience/intuition as Paradoxica described.

Here's some insights:

1) The fraction is polynomial of degree 1 divided by polynomial of degree 2. When you have this (degree of numerator is one less than degree of denominator), then you think of a logarithms.

2) The denominator is sum of two squares, think of tan.
following on from this,

pro tip for 1231, for these types of integrals will mostly be logs or the occasional case arctan
 

leehuan

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Re: MATH1231/1241/1251 SOS Thread

Is there a trick to use that's not induction?







 

Paradoxica

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MATH1231/1241/1251 SOS Thread

Is there a trick to use that's not induction?







1. The arithmetic mean of any two different real numbers strictly lies between them.
2. The geometric mean of any two different positive numbers strictly lies between them.
3. Use AM-GM for n=2.
 

Flop21

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Re: MATH1231/1241/1251 SOS Thread

dy^2/dt^2 + 4y = 0

how do i find the general solution of this equation?

I'm used to it in the form dy^2/dt^2 + dy/dt + 4y = 0.
 

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