Wait, wait, wait....
(B)
P(A|B) = P(A and B)/P(B) = 0.19/(0.19/1) = 0.19/1 = 0.19
(C)
For them to independent P(A|B) = P(A)
P(A|B) = 0.19 whereas P(A) = 0.31 <-----add up 0.19, 0.09. 0.03
My mistake was calculating probablity for just one day, instead of all 3.