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Awk moment when I'm stumped on Q4 (Help? :D) (1 Viewer)

Kanane

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A parabola whose equation is y=ax^2 where a is a constant' has the line y=12x+3 as a tangent.

By using the discriminant of the quadratic equation found, find the value of a


Thanks >_<
 

anne1010

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equate the two equations. ull get a quadratic. find the discriminant and since they touch one it should equal to 0. then solve for a :)
 

jnney

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ax^2 = 12x + 3

ax^2 - 12x - 3 = 0

delta = 144 + 12a

delta = 0 for tangent

144 = -12a

a = -12 :)
 

jnney

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Hehe no problem. Thanks for the rep.

Good luck for hsc!:)
 

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