HSC 2012-14 MX2 Integration Marathon (archive) (1 Viewer)

[Carrotsticks]

Re: MX2 Integration Marathon

Integral of e^[e^(x) +x].dx

That's a good question.

 

[HeroicPandas]

Re: MX2 Integration Marathon

That's a good question.

LOL, are u serious? Or are u joking with me O_O

 

[U MAD BRO]

Re: MX2 Integration Marathon


=)
i know it's wrong

 

[HeroicPandas]

Re: MX2 Integration Marathon

=)
i know it's wrong

DONT TELL HIM THE ANSWER!!!!, yeh im sorry its wrong, im from ext1 btw, i know a little of ext2 (tutor - complex numbers)

 

[HeroicPandas]

Re: MX2 Integration Marathon

im not saying that im better than you, i know u can beat me in ext and ext2

the question i posted up, u can use that way cos the power of e isnt a linear

 

[U MAD BRO]

Re: MX2 Integration Marathon

im not saying that im better than you, i know u can beat me in ext and ext2

the question i posted up, u can use that way cos the power of e isnt a linear

i hate mx1 !
do we use substitution?
do these then

and

 

[U MAD BRO]

Re: MX2 Integration Marathon

 

[HeroicPandas]

Re: MX2 Integration Marathon

i hate mx1 !
do we use substitution?
do these then

and

hm ok but try to do mine think b4 u use substitution think hard, u have to do something b4 u let u be something

 

[HeroicPandas]

Re: MX2 Integration Marathon

i hate mx1 !
do we use substitution?
do these then

and

LOL all this time i've been doing 4unit integration...i never knew that, feels good!
the first on is easy, i'll do the 2nd one

 

[barbernator]

Re: MX2 Integration Marathon

This is a double integral over a keystone shape in polar coordinates. (so limits are finite, and not a complete circle).

I've tried all sorts of things. I am not even sure if there is an analytic solution. Is there away to show there isn't one?

why do you post this, and you can't even do other simple questions?

 

[HeroicPandas]

Re: MX2 Integration Marathon

ahh its too hard, the 2nd one and 3rd one, IM MAD! its late now i gotta go to sleep, cya and remember to try to do my question

 

[HeroicPandas]

Re: MX2 Integration Marathon

why do you post this, and you can't even do other simple questions?

Integral of e^[e^(x) +x].dx

Goodnight

 

[U MAD BRO]

Re: MX2 Integration Marathon

why do you post this, and you can't even do other simple questions?

Which other questions are you referring to?

 

[U MAD BRO]

Re: MX2 Integration Marathon

ahh its too hard, the 2nd one and 3rd one, IM MAD! its late now i gotta go to sleep, cya and remember to try to do my question

nah, im gonna study harder 3U instead

 

[barbernator]

Re: MX2 Integration Marathon

<a href="http://www.codecogs.com/eqnedit.php?latex=\int e^{e^{x}@plus;x}=\int e^{e^{x}}e^{x}\\ let~u~=e^{x}\\ du=e^xdx\\ =e^{e^{x}} @plus; C" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\int e^{e^{x}+x}=\int e^{e^{x}}e^{x}\\ let~u~=e^{x}\\ du=e^xdx\\ =e^{e^{x}} + C" title="\int e^{e^{x}+x}=\int e^{e^{x}}e^{x}\\ let~u~=e^{x}\\ du=e^xdx\\ =e^{e^{x}} + C" /></a>

 

[U MAD BRO]

Re: MX2 Integration Marathon

is there a fast way to do this question?
the way i do it is with complex numbers and it gets really messy.

 

[barbernator]

Re: MX2 Integration Marathon

is there a fast way to do this question?
the way i do it is with complex numbers and it gets really messy.

u can do partial fracts but it takes bloody ages

 

[Sanjeet]

<a href="http://www.codecogs.com/eqnedit.php?latex=\int e^{e^{x}@plus;x}=\int e^{e^{x}}e^{x}\\ let~u~=e^{x}\\ du=e^xdx\\ =e^{e^{x}} @plus; C" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\int e^{e^{x}+x}=\int e^{e^{x}}e^{x}\\ let~u~=e^{x}\\ du=e^xdx\\ =e^{e^{x}} + C" title="\int e^{e^{x}+x}=\int e^{e^{x}}e^{x}\\ let~u~=e^{x}\\ du=e^xdx\\ =e^{e^{x}} + C" /></a>

Lol so simple, can't believe no one got it before

 

[asianese]

Re: MX2 Integration Marathon

Omg I just did the e^x one without anything!

 

[asianese]

Re: MX2 Integration Marathon