xy=c^2 (1 Viewer)

[Shady01]

Hey holisdays, studying 6 subjects at once, no teachers, mind is aray

to Find the gradient of xy=c^2
I have a point, need the equation

is it y=c^2/x
dy/dx= 2c/x

or is it? y=c^2/x
dy/dx=vu'-uv'/v^2
2cx-c^2/x^2
=c(2x-c)/x^2 ?

Or am I horribly wrong? And just embarrsed myself in front of the greatest minds of NSW? lol

 

[Riviet]

y=c²/x
=c²x^-1
Just treat c² as some constant when you're integrating with respect to x:
dy/dx=-c²x^-2
=-c²/x²

Sub. in your x coordinate of the point into dy/dx to find the gradient and use the point-gradient formula to find the equation of the tangent at that point.

 

[hyparzero]

Or just use implicit differentiation, then rearrange

 

[Shady01]

Ahhh C is a constant that makes sense, sorry Lotto I cant read what you've done with the whole _{thing? Could you help?}

 

[pLuvia]

Better?

 

[Shady01]

ahhhh No lotto you had explained it well before, its just I think you muddled up some of your coding. I understand now thank-you very much