Q 7(c) of the Cranbrook 2002 trial:
Consider a pack of 50 playing cards that consists of 5 colours (yellow, green, blue, indigo and violet), each of which contain cards numbered from 1 to 10 inclusive, respectively.
A joker is added to the pack. The joker can stand for any card and when there are equal numbers of different cards it takes the value of the higher card.
Otherwise, the joker stands for the card which is occurring most often.
e.g. two 4s, two 6s and a joker = two 4s and three 6s;
or two 4s, one 6, one 8 and a joker = three 4s, one 6 and one 8.
If five cards are dealt to a player, determine the probability (leaving your answer as a fraction in simplest form) that the player has received:
(i) four 10s
(ii) any three of one number and any two of another number, e.g. three 10s and two 8s
The answer we came up with for (i) is 9/156604, which may or may not be correct. Spice girl or others want to have a go?
And the answers we came up with for (ii) were 3/4606 and 300/39151, depending on the method.
Consider a pack of 50 playing cards that consists of 5 colours (yellow, green, blue, indigo and violet), each of which contain cards numbered from 1 to 10 inclusive, respectively.
A joker is added to the pack. The joker can stand for any card and when there are equal numbers of different cards it takes the value of the higher card.
Otherwise, the joker stands for the card which is occurring most often.
e.g. two 4s, two 6s and a joker = two 4s and three 6s;
or two 4s, one 6, one 8 and a joker = three 4s, one 6 and one 8.
If five cards are dealt to a player, determine the probability (leaving your answer as a fraction in simplest form) that the player has received:
(i) four 10s
(ii) any three of one number and any two of another number, e.g. three 10s and two 8s
The answer we came up with for (i) is 9/156604, which may or may not be correct. Spice girl or others want to have a go?
And the answers we came up with for (ii) were 3/4606 and 300/39151, depending on the method.