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Rax

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Hello Everybody

Started Volumes last week.

Just had one question

A hole of radius a/2 is bored through the centre of a sphere of radius a. Fine the volume of the remaning solid.

I am meant to be doing this by using slices not cylindrical shells.

Any ideas? I just can't get it off the ground

Thanks all

GG
 

_ShiFTy_

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I think you use slicing

Draw x<sup>2</sup> + y<sup>2</sup> = a<sup>2</sup> and dot x = -a/2 and +a/2
Your strip should be between any edge of the circle and x = -a/2
Spin this around the y axis and you should get:

Δv = π(x<sup>2</sup> - a<sup>2</sup>/4)Δy

*x<sup>2</sup> + y<sup>2</sup> = a<sup>2</sup>

2π <sub>0</sub>∫<sup>a</sup> (3a<sup>2</sup>/4 - y<sup>2</sup>) dy

I got 5π/6 . a<sup>3</sup> as the answer... :S
 
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Rax

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Yeah funny enough I did somethin similiar to that, and the answer is

(sqrt3)π/2 . a3

so its dodging me
 

_ShiFTy_

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Iruka said:
Draw a picture. Check your limits of integration - where does x=a/2 meet the circle?
Whoops...totally forgot about the change of limits
 

Rax

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Na, don't worry. My Teacher showed me how to do it properly.

I was doing it so wrong lol.

My bad.

GG
 

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