akataylor
Member
- Joined
- Sep 3, 2008
- Messages
- 42
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hi there,
i actually don't have a problem with understanding this topic, just a simple bit of algebra/indices (yup, i'm a noob)
question:
The area below the graph y = 1/x in the first quadrant and between x = 1 and x = 4 is rotated about the x axis...find the volume blah blah blah
alright, i know how to set it out, and i know that i need to make y into y squared. also, i know that my other "line" is the x axis too, since it needs to be in the first quadrant.
anyway, how can i get y^2? when changing y = 1/x to y=x^-1, when i square both sides, does it become y^2 = x^-2?
Sorry for the noob question, but thanks in anticipation
i actually don't have a problem with understanding this topic, just a simple bit of algebra/indices (yup, i'm a noob)
question:
The area below the graph y = 1/x in the first quadrant and between x = 1 and x = 4 is rotated about the x axis...find the volume blah blah blah
alright, i know how to set it out, and i know that i need to make y into y squared. also, i know that my other "line" is the x axis too, since it needs to be in the first quadrant.
anyway, how can i get y^2? when changing y = 1/x to y=x^-1, when i square both sides, does it become y^2 = x^-2?
Sorry for the noob question, but thanks in anticipation