URGENT Geometry help URGENT! (1 Viewer)

[el_manu]

Ok. You know how rhombus diagonals bisect the angles at the corners.

Does the same thing happen in squares?????

 

[InteGrand]

Ok. You know how rhombus diagonals bisect the angles at the corners.

Does the same thing happen in squares?????

Yes (a square is a special case of a rhombus, after all).

 

[sharoooooo]

yep.
if u need proof, i guess you could say like if u draw the diagonals in the square, itd form 4 isos triangles. and the diagonals bisect the right angles. so the base angles of each isos = 45. so then the other angle must be 90. thus, perpendicular

 

[InteGrand]

yep.
if u need proof, i guess you could say like if u draw the diagonals in the square, itd form 4 isos triangles. and the diagonals bisect the right angles. so the base angles of each isos = 45. so then the other angle must be 90. thus, perpendicular

He wasn't asking whether the diagonals bisect each other at right angles (which they do), but whether the diagonals bisect the square's internal angles (which they also do). (This is easily proved by drawing a diagonal and noting that the triangles formed are isosceles and congruent.)