i like using that "method". used 1000 for infinity.Originally posted by Calculon
if in doubt substitute in 0.00001, not very methodical but it works.
in an exam can u jus put that as the answer, or jus state since lim x-> 0 for sinqx/sinzx = q/z? dont u need workin out?Originally posted by Calculon
When you have a limit with sinqx/sinzx and x-->0 it ends up being q/z. The answer to this one is 4*3/2=6
I don't think you'd be allowed to assume that.Originally posted by Calculon
When you have a limit with sinqx/sinzx and x-->0 it ends up being q/z. The answer to this one is 4*3/2=6
if in doubt substitute in 0.00001, not very methodical but it works.
But it's a VERY good check to see if you're right. Saved my ass in 3 unit.Originally posted by ND
I don't think you'd be allowed to assume that.