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But NaOH is a strong base, so when in the solution, the OH- wants H+, which it gets from the CH3COOH, so there's no problem with it.Originally posted by +:: $i[Q]u3 ::+
good point.
but then again.. we titrated vinegar wit naoh in class to find the conc. of acetic acid in original indiluted vinegar - a bit dodge when u consider ch3cooh only partially ionises.