STANDARD POTENTIALS - oxidisation and reduction (1 Viewer)

darksouljah

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hello,

"Chemical species, such as metals, that cause reduction are called reductants. Chemcial species, such as metal ions, that cause oxidation are called oxidants." (Macquarie HSC Chemistry (page 16))

Just checking,
does reductants use the oxidation and oxidants use reduction?

AND.........>>>>
looking at the Standard potentials Table ...

Is k+e>>K(s) the highest oxidation state?
and is F2(g) + 2e>>2F the highest reduction state?

, im confused alot with this.... just want to make clear before staring electrolysis.

Thanks very much,



<table style="width: 346px; height: 139px;" border="1" cellpadding="2" cellspacing="2"><tbody><tr><td>K<sup>+</sup>(aq) + e<sup>-</sup> → K(s)</td><td><center> -2.92</center></td></tr> <tr><td>Ca<sup>2+</sup>(aq) + 2e<sup>-</sup> → Ca(s)</td><td><center> -2.76</center></td></tr> <tr><td>Na<sup>+</sup>(aq) + e<sup>-</sup> → Na(s)</td><td><center> -2.71</center></td></tr> <tr><td>Zn<sup>2+</sup>(aq) + 2e<sup>-</sup> → Zn(s)</td><td><center> -0.76</center></td></tr> <tr><td>Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>→ Cu(s)</td><td><center> 0.34</center></td></tr> <tr><td>O<sub>3</sub>(g) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> → O<sub>2</sub>(g) + H<sub>2</sub>O(l)</td><td><center> 2.07</center></td></tr> <tr><td>F<sub>2</sub>(g) + 2e<sup>-</sup>→ 2F<sup>-</sup>(aq)</td><td><center> 2.87</center></td></tr></tbody></table>
 
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xiao1985

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K(s) is most likely to oxidise

F2(g) is most likely to reduce
 

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