# Someone post up the answers :D (1 Viewer)

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#### jessicaaa.

##### New Member
Yes, please, I need to work out roughly what I got

#### sdx91

##### Member
if you think you lost <30 marks then you will get over 75%

#### MrKim

##### Member
Well why dont someone ask a question that they wanted to know about, then others can help and give their answers. Compare and voila.

As for me, i wanted to know the answer in regards to the monthly payment part (ii) i think it was. I got something like 100~ something, i dont know if this is correct. Someone know?

#### jessi90

##### Member
i think i got 975.8

#### jessicaaa.

##### New Member
I got \$985. something.

I originally got 975...but I thought I messed up the formula, so I changed it.

I got \$975.85

#### MrKim

##### Member
There goes a couple of marks..

#### Rampager

##### Member
Question 9 b) ii) \$975.

Question 10 a) 5ln5 - 4

Question 7 a) e^(3) and e^(-1)

Question 6c) 18.75(PI) units^2

Question 6b)i) 20
ii) t = 10
iii) t = 6
iv) forget.

Last edited:

#### BackCountrySnow

##### Active Member
yeah, i got somewhere in the 900s.

#### ewasemma

##### New Member
Hey guys just wondering.. what would an 86/120 be roughly as a moderated mark for maths. thanks

#### iluvGG

##### Member
harryboyles said:
I got \$975.85
yes! i got exactly that!! hope its right. lol

#### Rampager

##### Member
ewasemma said:
Hey guys just wondering.. what would an 86/120 be roughly as a moderated mark for maths. thanks
Band 4, unlikely Band 5.

#### BackCountrySnow

##### Active Member
Rampager said:
Question 6b)
iii) t = 6
yes i cbf quoting the ppl saying it isnt.
but here is why it is t=6:

what is acceleration?
It is the change in velocity over time.

And how do we measure this change?

yes, and when is the gradient 0?
umm, at the maximum, when 't' equals zero?

oh wow, correct.

#### ewasemma

##### New Member
Rampager said:
Band 4, unlikely Band 5.
:S I really wanted a band 5

#### chook 05

##### Sum Fulla
was question #9 c) (ii) = 1/6kb^4 units below axis?

#### minijumbuk

##### ┗(^o^ )┓三
chook 05 said:
was question #9 c) (ii) = 1/6kb^4 units below axis?
f'(x) = k(b2x - x3/3)
f(x) = k(b2x2 - x4/12) + C

When x = b, y = 0

0 = k(b4/2 - b4/12) + C
C = - 5b4k/12

f(x) = k(b2x2 - x4/12) + - 5b4k/12

When x = 0,
f(x) = - 5b4k/12
Therefore 5b4k/12 below x-axis

#### chrisbos2007

##### Member
what do you guys think a 80/120 will end up being??

70-80? or what

#### ipod21

##### Member
Rampager said:
Question 7 a) e^(3) and e^(-1)

Question 6b)
iv) forget.
Q 7a) i got X= 2e^(-3)
6b) iv) 1480/3