SC mathematics Marathon (2 Viewers)

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
Let Opposite side = 4a
Let Adjacent side = 3a
(sinx=4a/3a=4/3)

(4a)^2+(3a)^2=32^2

16a^2+9a^2= 1024

25a^2=1024

a^2=1024/25

sqrt(a^2)=sqrt(1024/25)

a=32/5

4a= 25.6

:. the opposite side is 25.6 cm

There are probably easier ways to do this, but I like to solve it my way.

Take an isosceles triangle
Draw a line from one vertex to the midpoint of the opposite side
Do so for all 3 vertices
Now Prove the 3 lines you drew are all equal in length
sin(x)=Opp./Hyp.=/=Opp./Adj.
 

dionb2014

Member
Joined
Aug 8, 2011
Messages
431
Location
Sydney
Gender
Male
HSC
2014
draw a tree diagram of the possible results for 1st spin. Then accumulate the possible results with the next spin.

1-2,5,8
7-14,8,10,11
3-6,7,10,4
4-7,8,11,5

8 is the most frequent and I know I explained that quite badly.
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
can someone explain this please?
Assuming all integers have equal possibility:

Possibilities:
1+1 =2
1+3 =4
1+4 =5
1+7 =8

3+3 =6
3+4 =7
3+7 =10

4+4 =8
4+7 =11

7+7 =14

Now if you look at these scores, you will find the mode to be 8
Not a very mathematical way of doing this question, but hey, its multiple choice
 

dionb2014

Member
Joined
Aug 8, 2011
Messages
431
Location
Sydney
Gender
Male
HSC
2014
Tom and Bill hunted sheep in a ratio of 10:2
if all together they killed 144 sheep. How many did bill kill?
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
FIRST ATTEMPT AT THIS QUESTION WAS WRONG
Im so stupid, this question is incredibly simple

let a=opposite

a/32=4/3

3a=128
a=128/3
sin(x)=Opp./Hyp.=/=Opp./Adj.
Fixed

Tom and Bill hunted sheep in a ratio of 10:2
if all together they killed 144 sheep. How many did bill kill?
For every 12 sheep killed, Tom killed 10 and Bill killed 2
:. For every 144 sheep killed, Tom killed 120 and Bill killed 24
 

knxd

Member
Joined
Jul 17, 2011
Messages
135
Gender
Male
HSC
2013
draw a tree diagram of the possible results for 1st spin. Then accumulate the possible results with the next spin.

1-2,5,8
7-14,8,10,11
3-6,7,10,4
4-7,8,11,5

8 is the most frequent and I know I explained that quite badly.
Assuming all integers have equal possibility:

Possibilities:
1+1 =2
1+3 =4
1+4 =5
1+7 =8

3+3 =6
3+4 =7
3+7 =10

4+4 =8
4+7 =11

7+7 =14

Now if you look at these scores, you will find the mode to be 8
Not a very mathematical way of doing this question, but hey, its multiple choice
Thanks!
 

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013
FIRST ATTEMPT AT THIS QUESTION WAS WRONG
Im so stupid, this question is incredibly simple

let a=opposite

a/32=4/3

3a=128
a=128/3
Opposite side can't be greater than the hypotenuse, question doesn't work.
 

nazfiz

Member
Joined
Feb 3, 2010
Messages
121
Gender
Male
HSC
2013
Tom and Bill hunted sheep in a ratio of 10:2
if all together they killed 144 sheep. How many did bill kill?
Adding the ratios together gives you 12
144/12= 12
hence 12 sheep equal one portion
so Bill's amount is given by
2x 12= 24
 

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013
A harder probability question, but why not:

I have a hat filled with all the prime numbers between 1 and 15. What is the probability that if I pick out 2 numbers and multiply them, the result will be an even number.
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
A harder probability question, but why not:

I have a hat filled with all the prime numbers between 1 and 15. What is the probability that if I pick out 2 numbers and multiply them, the result will be an even number.
Product of two odd numbers are always odd
2 is the only series that applies
However repetition does not count because you are taking balls out of the bag
The number of possibilities = 6! (6x5x4x3x2x1)
Number of possibilties without repetition = 6!-6
=714

Number of 2 series that does not repeat = 5
:. 5/714 is the probability of drawing an even number out of the bag

Im either completely right or just plain wrong (I have a feeling its the latter)
 

nazfiz

Member
Joined
Feb 3, 2010
Messages
121
Gender
Male
HSC
2013
2010 sc
q83 (C) (ii)
tyy
ABCD is a kite.
The area of a kite is given by 1/2xy (x and y being diagonals)
so from multiply the answer from part i by two to gain the area of the entire kite. so
168= 1/2x 25 x BD
BD= 13.44
 

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
Product of two odd numbers are always odd
2 is the only series that applies
However repetition does not count because you are taking balls out of the bag
The number of possibilities = 6! (6x5x4x3x2x1)
Number of possibilties without repetition = 6!-6
=714

Number of 2 series that does not repeat = 5
:. 5/714 is the probability of drawing an even number out of the bag

Im either completely right or just plain wrong (I have a feeling its the latter)
lol dude, i did it the long way and got 1/3
 

applepopper

Member
Joined
Nov 3, 2011
Messages
30
Location
Sydney
Gender
Male
HSC
2013
Uni Grad
2017
hi guys
noob question how do i post an image im trying to get this question up :D
 
Last edited:

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
lol dude, i did it the long way and got 1/3
Damn it, I always do something wrong somehow. Ill redo it because I think Ive seen where my logic has gone wrong.
Prime Numbers (Reference): 2, 3, 5, 7, 11, 13
(The next paragraph is a personal note)
When you select the first ball, the probability of getting a particular ball is 1/6, then second ball you draw out is 1/5. If I wanted to draw the ball 2 and 3 for instance, then the probability of that is 1/30 (6x5)
Probability of any combo that has 2 in it is: 5/30 = 1/6

Therefore the probability is 1/6?

Please show me how you did it
 

lath

Member
Joined
Oct 6, 2010
Messages
127
Gender
Male
HSC
2013
Damn it, I always do something wrong somehow. Ill redo it because I think Ive seen where my logic has gone wrong.
Prime Numbers (Reference): 2, 3, 5, 7, 11, 13
(The next paragraph is a personal note)
When you select the first ball, the probability of getting a particular ball is 1/6, then second ball you draw out is 1/5. If I wanted to draw the ball 2 and 3 for instance, then the probability of that is 1/30 (6x5)
Probability of any combo that has 2 in it is: 5/30 = 1/6

Therefore the probability is 1/6?

Please show me how you did it
you forgot 3,2; 5,2; 7;2 etc.
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
you forgot 3,2; 5,2; 7;2 etc.
I had the impression that
2;3 is the same as 3;2 etc.?
If so then Im probably right, if not then you are right
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top