Ratios Question (1 Viewer)

[Ambility]

I believe the answer to this question is 1:2, but the answers say it is 2:1. Could someone tell me what they get as their answer?

 

[Drongoski]

You are right. PC:CQ is indeed 1:2

I did not solve the problem; I just sketched the line and P, C and Q and made a visual inspection.

 

[InteGrand]

I believe the answer to this question is 1:2, but the answers say it is 2:1. Could someone tell me what they get as their answer?

What was your working? Maybe we can see what you did wrong (if anything).

 

[Nailgun]

solved the question
got 1:2

pc = 5/3
cq = 10/3

 

[Ambility]

What was your working? Maybe we can see what you did wrong (if anything).

I'm pretty sure I'm right, but I'll give you my working just so you can check.

http://i.imgur.com/jlpR81R.jpg

 

[InteGrand]

I'm pretty sure I'm right, but I'll give you my working just so you can check.

http://i.imgur.com/jlpR81R.jpg

Your answer is right, as the others have also said.

 

[si2136]

TIP: Try not to do your test in frixon pen. They don't allow it in the HSC. Because it allows the rubbing of the ink on the paper, which can allow cheating, even if it wasn't intended to be.

 

[Drongoski]

Another approach without finding the intersection point C.

Signed distances from P and Q to the given straight line in the ratio:



The opposite signs show that P and Q are on opposite sides of the given line, as we would require.

Now the ratio above, ignoring signs, is for the perpendicular distances of P and Q from the line. But this is the same ratio as PC:CQ by virtue of similar triangles formed by the 2 dropped perpendiculars and PC and QC.