• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

rates of change question (1 Viewer)

karen88

Radioactive Queen
Joined
Jun 21, 2004
Messages
197
Location
Sydney
Gender
Female
HSC
2005
a liquid in a vessel is allowed to flow out through a tap in the bottom at a rate given by dV/dt=-10(40-t) where v cm^3 is the volume of the liquid in the vessel at time t seconds

initially the vessel contained 8.0 litres of liquid. find the amount of liquid in the vessel after 10 secs...

help... dun noe where to start...
 

FinalFantasy

Active Member
Joined
Jun 25, 2004
Messages
1,179
Gender
Male
HSC
2005
karen88 said:
a liquid in a vessel is allowed to flow out through a tap in the bottom at a rate given by dV/dt=-10(40-t) where v cm^3 is the volume of the liquid in the vessel at time t seconds

initially the vessel contained 8.0 litres of liquid. find the amount of liquid in the vessel after 10 secs...

help... dun noe where to start...
dV/dt=-10(40-t)
V=int. -10(40-t) dt=-10 (40t-t²\2)+c
at t=0, V=8000
.: 8000=c
.: V=-10(40t-t²\2)+8000
at t=10, V=-10(400-50)+8000=4500cm^3
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top