probability. (1 Viewer)

hbk_ace

your all F**k Liars
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Originally posted by underthesun
Just curious.

I got i) n^n

and for the second, (n^n - n!)/n^n

is that what yous got?
one question im sure i got right
 

hbk_ace

your all F**k Liars
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Originally posted by walla
hang on a sec
surely its quite simple
P(at least one door not chosen) = 1 - p(all doors chosen)
since there are n people and n doors,
the first person can choose n, the second person can choose (n-1) etc
then p(all doors chosen) = n!
then p(at least one door not chosen) = 1 - n!
but 1 - n! /n^n cause the probability has to be over the total outcome
 

deyveed

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Originally posted by hbk_ace
but 1 - n! /n^n cause the probability has to be over the total outcome
Oh sh*t. I just lost a mark there. *sniff*
i had 1- n!
 

MyLuv

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I got n^n- n!
But i didnt find the proability.There goes 1 easy mark:chainsaw:
(saw it after the stop the exam but wouldnt dare to put /n^n in:( )
 

smeyo

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Sep 16, 2003
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yeah i got the same as most here, luckily i was sure it just didnt look right cause it was a little easy and siple to derive so i was almost tempted to change it to.. luckily i didnt
 

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