Modern4DaBois
Member
- Joined
- Oct 25, 2021
- Messages
- 42
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- Male
- HSC
- 2022
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Ah kk That makes sense now. Thanks!For question 17, a polynomialcan inly have a multiple root if there are any
-values for which
, using the multiple root theorem. If you attempt to solve the equation
, you should find it has only one solution,
. However,
and so the only potential multiple root isn't a root at all, and so there are no multiple roots.
In fact, ifis extended to an infinite polynomial, it is the polynomial version of
, as indicated by the fact that you then have
and thus there are no zeroes of
at all.
Thank you, I hope that they make sense and help lots of BoS contributors.Ah kk That makes sense now. Thanks!
Your explanations are really good btw.