Aerath
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A body is projected vertically upwards from he Earth's Surface with velocity U. The acceleration of a particle in space is given by k/x^2 towards cenre of the earth, where x is the distance of the body from the centre of the earth. Given that the acceleration is g at the earth's surface, prove that the velocity v, at time t is given by v^2 = U^2 - 2gR^2 ( 1/R - 1/x), where R is the radius of the earth.
(Done that bit)
If U^2 = 2gR, find dx/dt in terms of x and show that the body will reach a distance 8R from the earth's surface, in a time of 2.72 hours.
I keep getting 0.86 =\.
(Done that bit)
If U^2 = 2gR, find dx/dt in terms of x and show that the body will reach a distance 8R from the earth's surface, in a time of 2.72 hours.
I keep getting 0.86 =\.