wow...so hard >.>..It will be hard to break down the question during the exam >.>.(9 times the age of the son)+5 divided by sons age +5.
Makes perfect sense.
wow...so hard >.>..It will be hard to break down the question during the exam >.>.(9 times the age of the son)+5 divided by sons age +5.
Makes perfect sense.
my math is really bad, but i'd guess it'd be 4cm coz 2 of the sides would be the same length, since the top and the bottom are likely to be longer than the side lengths that connect them, i'd guess that it's for. ROFL sozz, im not too good with using formulas :Sty guys and this one as welll
a trapezium has 3 sides which are 4 cm, 10 cm and 13 cm.... the 4th side is x need to find x and the perimeter of the trapezium???
last side is 5 cos of pythag. so the perimeter is 32cmty guys and this one as welll
a trapezium has 3 sides which are 4 cm, 10 cm and 13 cm.... the 4th side is x need to find x and the perimeter of the trapezium???
ugh does this mean (q^2)/(p-2)???A question I got wrong in my trial: "Write an expression for the quotient of q^2 and 2 less than p." Does anyone know how to approach this?
Oh this was in my trial.A question I got wrong in my trial: "Write an expression for the quotient of q^2 and 2 less than p." Does anyone know how to approach this?
Oh this was in my trial.
The answer is
q^2
------
p-2
I have no idea.
Also, anyone have any tips for multiplications in the non calculator section like this:
77 x 15 + 23 x 15 =
what should I do in my head?
OOOOHHHH i have a better methodquotient is division. Just the division word like addition (plus), subtraction (minus), product (times).
Therefore:
q^2 divided by p-2
Make it a fraction! q^2 over p-2
77 x 15 + 23 x 15
Do it on paper. Multiply the first bit (put in your own brackets), then multiply the second bit, then add them.
(77 x 15) + (23 x 15)
well at least it isn't maths debating xD jksjks dont sue meSorry about the world's worst pun.
Umm, well, I know it's not as necessary, but I won't study maths if it's not on BoS tonight, so I started. Everyone join in!
Don't know how this will work, just copy and paste questions from past papers I suppose. Here goes!
Question:
Jarrod has 43 stickers, Timothy has 27 and Abigail has 14. Jarrod wants them to
share the stickers equally.
How many stickers will Jarrod have to give away so that all three children have
the same number of stickers?
oh 22. its 1/3 i think and for 24. 11 is the first number and it increases by 4 so u get 11 + 4(150-1) = 607 its 150-1 coz the first number is elevenHelp pleasseee.
22. In a store freezer, there are a number of cartons of milk.
The ratio of the cartons containing chocolate, vanilla and strawberry milk is:
3:2:1
If half the cartons of chocolate milk are sold, what fraction of the cartons remaining in the freezer are still chocolate?
Sorry for all the questions but I'll answer the ones I know!
24. What is the 150th number in the sequence: 11, 15, 19, 23 ........ ?
How do I do that ^ Lol?
3:2:1 = 6:4:2I think I kinda get why it's 150-1.. Still not sure..
How did you get 1/3 for the milk Question?
It's stumped me. I hate ratios.
Thankyou. Verrrrry much3:2:1 = 6:4:2
Half of chocolate gone - 3:4:2
Fraction of the cartons remaining - 3/9 = 1/3
Formula: Tn= a + (n-1)d24. What is the 150th number in the sequence: 11, 15, 19, 23 ........ ?
How do I do that ^ Lol?
1 buildermy question off the top of my head... 3 builders complete a job in 40min
how long for 5?