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Dubble-u25 · Sep 26, 2011

$\lim_{x\rightarrow 0}\frac{1- cos 2x}{x^{2}}$

How would u work this one out?
Thanks in advance !

nightweaver066 · Sep 26, 2011

Drongoski · Sep 26, 2011

For those not so well-versed in limits:

$\lim_ {x \to 0} \frac {2 sin^2 x}{x^2} = 2 \lim_ {x \to 0} \frac {sin x}{x} \times \lim _{x \to 0} \frac {sin x}{x} = 2 \times 1 \times 1 = 2$

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Dubble-u25

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