d/dx (uv) = u(dv/dx)+v(du/dx)

take the integral with respect to x of both sides:

uv = ∫ u(dv/dx ) dx + ∫ v(du/dx) dx

therefore,

∫ u(dv/dx ) dx = uv - ∫ v(du/dx) dx

If this method is incorrect, I would appreciate if anyone could tell me how to actually do it.

Cheers,

SB