SB257426
Very Important User
I am pretty confused with my solution to this integration proof question. I feel like it isn't the right way to prove it.
d/dx (uv) = u(dv/dx)+v(du/dx)
take the integral with respect to x of both sides:
uv = ∫ u(dv/dx ) dx + ∫ v(du/dx) dx
therefore,
∫ u(dv/dx ) dx = uv - ∫ v(du/dx) dx
If this method is incorrect, I would appreciate if anyone could tell me how to actually do it.
Cheers,
SB
![Screen Shot 2023-01-19 at 10.03.25 pm.jpg](/data/attachments/37/37510-3bc45e02f51f19f3ff089a8f1bec21ff.jpg)
d/dx (uv) = u(dv/dx)+v(du/dx)
take the integral with respect to x of both sides:
uv = ∫ u(dv/dx ) dx + ∫ v(du/dx) dx
therefore,
∫ u(dv/dx ) dx = uv - ∫ v(du/dx) dx
If this method is incorrect, I would appreciate if anyone could tell me how to actually do it.
Cheers,
SB