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integration by substituon (1 Viewer)

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bos1234

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ah kk.. thanks for the quickly reply man
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STx

STx

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^ he means- dont integrate p and q.

So u=qx^2 - 3, du=(2qx)dx, xdx=du/2q
(p/2q)∫(u^3)du
=(3p/2q).[qx^2 - 3]^2
 
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