bob fossil
Member
can someone please show me how to derive x/y and x^2/y^2 w.r.t x
thank you
thank you
d/dx (x/y) = (y+xy')/y^2 [By quotient rule]can someone please show me how to derive x/y and x^2/y^2 w.r.t x
thank you
d/dx (x/y) = (y+xy')/y^2 [By quotient rule]
d/dx (x^2/y^2)
= d/dx ((x/y)^2)
= 2(x/y).d/dx (x/y) [By chain rule]
= 2x/y.(y+xy')/y^2
= 2x(y+xy')/y^3
Might be a problem in the solution.
Just treat it as a normal derivative but when differentiating y wrt x, let d/dx (y)=dy/dx=y'
Thank you
does this also = 2(x/y).xy= 2(x/y).d/dx (x/y)
Yeah, it should. I'm not entirely sure if my answers are correct though.does this also = 2(x/y).xy
I know it's picky, but you actually "differentiate". Deriving is different.can someone please show me how to derive x/y and x^2/y^2 w.r.t x
thank you
LOL, I had typed something similar to this, but then thought meh. Glad someone said it xDI know it's picky, but you actually "differentiate". Deriving is different.
i really need to learn the language lol i got the first letter right lolI know it's picky, but you actually "differentiate". Deriving is different.