help (1 Viewer)

[user18181818]

 

[SadCeliac]

bro idfk sorry been trying for ten minutes

what's your thought process?

 

[user18181818]

idk if this is even remotely right but i did 100/1.060 to get 94.33...mL which is 0.09433..L
i then found moles of mgso47h20 which is0.05679... and then divided it by the volume to get molarity but it's 0.602...mol/L
and the answer is B i think - i found it on a discord channel

 

[SadCeliac]

if you just do it without including density, you get B, so I think B is incorrect;

molar mass of the whole thingy is 246, so you do 14g/246g/mol = 0.0569mol --> in 100ml
therefore in 1L it's 0.569 mol/L which is B so I think B is wrong

lol that's all I've figured out

 

[user18181818]

ohhh yeah makes sense they just didn't include density

 

[user18181818]

thanks man

 

[wizzkids]

The mass of solution is M= 14 g + 100 g = 114 g The density rho ρ of the solution is ρ= 1.060 g/mL so divide M by ρ and you get V=107 mL of solution. The 14 grams of the hydrous MgSO₄.7H₂O contains n = 0.0568 moles. Therefore divide n by V and you get 0.53 mol/L

 

[rainbowspoon1]

I got D, 100g + 14g = 114g, divide by 1.060, you get 107.54 which is the volume of the solution. c = n/v, n = 14/120.366, v = 0.10754. therefore c = 1.08 M (3.S.F)

 

[rainbowspoon1]

I got D, 100g + 14g = 114g, divide by 1.060, you get 107.54 which is the volume of the solution. c = n/v, n = 14/120.366, v = 0.10754. therefore c = 1.08 M (3.S.F)

oops the person who got 0.53 is correct, i didnt include the h20 in the molar mass