jonathanrsh
New Member
- Joined
 - Jul 5, 2011
 
- Messages
 - 3
 
- Gender
 - Male
 
- HSC
 - 2011
 
1/z is the conjugate of z, no?
so l 1+1/z l = l 1+z-iy l = sqrt([1+z]^2 + [y]^2)
Square both sides, and you get a circle...
	
		
			
		
		
	
								so l 1+1/z l = l 1+z-iy l = sqrt([1+z]^2 + [y]^2)
Square both sides, and you get a circle...
				