Ok the question is:
Solve 2e^5t = 75 to 3 sig fig's.
I worked it out like this:
log2e^5t = log75
5tlog2e = log75
5t = log75 / log2e
.:. t = 0.509
Now im pretty sure ive got the process right, but im not sure if im putting the log2e in the calculator correctly. I put it in e1 = blah, then blahx2 then I log it. Is that right?
The back of the book says its 0.725
Solve 2e^5t = 75 to 3 sig fig's.
I worked it out like this:
log2e^5t = log75
5tlog2e = log75
5t = log75 / log2e
.:. t = 0.509
Now im pretty sure ive got the process right, but im not sure if im putting the log2e in the calculator correctly. I put it in e1 = blah, then blahx2 then I log it. Is that right?
The back of the book says its 0.725
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