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ellipse qn (1 Viewer)

bos1234

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then sub in pt (0,0) to satisfy eqn?

is this how you do this qn?
the worked soln. has 1 more step...

 

SeDaTeD

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Well it is completely valid, though it seems a bit unnecessary, unless you were actually told to find the equation of the chord then sub the point in.

Hint: note that cos(theta + pi) = - cos(theta) and sin(theta + pi) = -sin(theta) and the fact that the midpoint of any two points must lie of the line joining those two points.
 

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