Division of an Interval (1 Viewer)

zannasheayarrow · May 7, 2012

Can someone help me please.

A and B have co-ordinates (-1,7) and (5, -2) respectively. P divides the interval AB in the ratio k:1. Write down the co-ordinates in terms of k and hence find AP

B when P lies on the line 5x - 4y - 1 = 0

math man · May 7, 2012

The division formula as you know is:

$x_{0}=\frac{mx_{2}+nx_{1}}{m+n} \\ y_{0}=\frac{my_{2}+ny_{1}}{m+n}$

subbing in m=k and n=1 and A and B gives:

$x_{0}=\frac{5k-1}{k+1} \\ y_{0}=\frac{7-2k}{k+1}, \; where \\ P=(x_{0},y_{0}$

the question wants you to find k, so you all do now is sub P into the given line and solve for k.

Division of an Interval (1 Viewer)

zannasheayarrow

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math man

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