Constant Velocity and Acceleration (1 Viewer)

[Dt 08]

Hey

I am having troubles with how the constant velocity formula is derived;
(u+v)
2
Any ideas??

Also, are all the acceleration formulae we learn in the motion topic including the formula;
a= (delta)v
(delta)t
only applicable for constant acceleration??

Thanking you in advance

 

[vulgarfraction]

If velocity's constant, u=v so (u+v)/2=v.

Yes, that's true for constant acceleration, but if acceleration changes, then that's just average acceleration.

(Please don't underline to make it look like fractions.... eww.)

 

[watatank]

Also, are all the acceleration formulae we learn in the motion topic including the formula;
a= (delta)v
(delta)t
only applicable for constant acceleration??

Thanking you in advance

delta means like "rate of change in" you will understand this more when you do differentiation in maths (if you do maths)

acceleration is defined as the rate of change of velocity (it implies over a period of time)
a = delta v/delta t = change in velocity/ change in time = (v - u)/ t

 

[Dt 08]

If velocity's constant, u=v so (u+v)/2=v.

Yes, that's true for constant acceleration, but if acceleration changes, then that's just average acceleration.

(Please don't underline to make it look like fractions.... eww.)

lol ill remember that fractions advise

so if acceleration is non-uniform, these formulae are useless?