Concavity..? (1 Viewer)

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
So, there's always a part in a question which asks "Find for which values of x is f(x) concave up [or down]" - usually for some cubic curve for Geometrical Applications of Differentiation.

I'm not 100% sure how to approach this. I know there's a way to do it graphically, but I'd like to know the algebraic method please.

Thanks in advance!
 

boxhunter91

Member
Joined
Nov 16, 2007
Messages
736
Gender
Male
HSC
2009
ahh yes to do this you need an expression for f"(x) say f"(x)= x-1
If it is maximum then f"(x)<0
.: x-1<0
.:x<1
 

untouchablecuz

Active Member
Joined
Mar 25, 2008
Messages
1,693
Gender
Male
HSC
2009
So, there's always a part in a question which asks "Find for which values of x is f(x) concave up [or down]" - usually for some cubic curve for Geometrical Applications of Differentiation.

I'm not 100% sure how to approach this. I know there's a way to do it graphically, but I'd like to know the algebraic method please.

Thanks in advance!
well

if y=f(x) is concave down at x=a, then f''(a)<0 => solve f''(x)<0 to find the range of x values for which f(x) is concave down

if y=f(x) is concave up at x=a, then f''(a)>0 => solve f''(x)>0 to find the range of x values for which f(x) is concave up

e.g.

f(x)=ax^3+bx^2+cx+d
f'(x)=3ax^2+2bx+c
f''(x)=6ax+2b

for points at which f(x) is concave down,

f''(x)<0 => 6ax+2b<0 and hence x<-b/3a
 

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
But you use f"(x) > 0 and f"(x) < 0 for testing the nature of stationary points, don't you?
 

kelllly

Member
Joined
Oct 7, 2009
Messages
89
Gender
Female
HSC
2009
Another example for you :):

Let's say the question is 'find for which values of x is f(x) = x^3 + x^2 concave down.'

1. First, find the first and second derivative:

f'(x) = 3x^2 + 2x
f''(x) = 6x + 2

2. Then, find the values of x for which the second derviative is negative*.

f''(x) < 0
6x + 2 < 0
6x < -2
x < -1/3

Answer: For x < -1/3 is f(x) = x^3 + x^2 concave down.


*I remember it like this:

Concave down = Unhappy = Negative
f''(x) < 0

Concave up = Happy = Positive
f''(x) > 0
 

kelllly

Member
Joined
Oct 7, 2009
Messages
89
Gender
Female
HSC
2009
But you use f"(x) > 0 and f"(x) < 0 for testing the nature of stationary points, don't you?
Yes, you do.

The second derivative is used to determine concavity.

Taking the example of a parabola:

A maximum stationary point corresponds with a concave down parabola.
A minimum stationary point corresponds with a concave up parabola.
 

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
Ah, thanks!

I'd been very confused, because the second derivative is used to both determine the nature of stationary points AND finding what x values give a concave up/down curve.

It's clear now. Thanks everyone!
 

Makro

Porcupine
Joined
May 16, 2006
Messages
415
Location
In between.
Gender
Male
HSC
2009
Or smiley face and upside down smiley face for the General kids.

f'(x) = gradient
f''(x) = concavity

Two things that I just think are nice to know without having to think.
 

Cloesd

Member
Joined
Nov 4, 2008
Messages
156
Gender
Male
HSC
2009
Or smiley face and upside down smiley face for the General kids.

f'(x) = gradient
f''(x) = concavity

Two things that I just think are nice to know without having to think.
What if the question asks, FIND ALL X for which a line is concave up. You go through the normal process yes..


f''(x) < 0
f''(x) = 12x(x-3)
12x(x-3) < 0

x < 3 and x < 0?

But if x is less than three, its already less than 0!, The back of the book says that its meant to be x is greater than 0, but less than three.

Or am i messing up the signs?

12x < 0
thus...
x > 0?

But that makes no sense.

What am i failing at?
 

Lukybear

Active Member
Joined
May 6, 2008
Messages
1,466
Gender
Male
HSC
2010
Draw the parabola, hence x intercepts are 0 and 3. Shade below the graph to indicate <0.

I.e.
\___/
0 \..../ 3

thus 0<x<3
 

kelllly

Member
Joined
Oct 7, 2009
Messages
89
Gender
Female
HSC
2009
What if the question asks, FIND ALL X for which a line is concave up. You go through the normal process yes..


f''(x) < 0
f''(x) = 12x(x-3)
12x(x-3) < 0
12x(x - 3) > 0
Concave up means f''(x) > 0

As Lukybear said, draw the parabola (attached).

From the graph, 12x(x - 3) > 0 (or positive) when:
x < 0
x > 3


BUT since you say the answer is 0 < x < 3, I assume you meant 'concave down'?

In that case, from the graph (again), 12x(x - 3) < 0 (or negative) when:
0 < x < 3
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top