Complex Number Equation (1 Viewer)

[Utility]

Solve (x²+6) + xi = 3(2+3i)(1-i)

I ended up with (x²+6) + xi = 15 + 3i & solved xi = 3i to get x = 3.

I'm wondering how else people do this?

 

[SpiralFlex]

 

[seanieg89]

Is it stated that x is real? If not then there is a second solution.

 

[SpiralFlex]

I assumed x was real.

 

[Utility]

Shouldn't it read 15 + 3i and x = 3 as the only solution?

 

[SpiralFlex]

Yup typo. Here we assume x is real. If it doesn't say then we need a different approach. Does it say x is real?

 

[Utility]

Good, that is the way I did it too. Thanks.

It doesn't say, but the solution was x = 3 in the book as well.