Calculus Question (1 Viewer)

Getteral09

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hey everyone, hope u guys have a great holiday!:)

I have a calculus question which i need help on. Here it is:

Differentiate
a) 2/x^4 + 1/5x^2



Thanks heaps,


From Getteral
 

alexvincent

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<SUP></SUP><?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:eek:ffice:eek:ffice" /><o:p>d/dx [2/x<SUP>4</SUP> + 1/5x<SUP>2</SUP>] = 2x<SUP>-4</SUP> + x<SUP>-2</SUP>/5<o:p></o:p>
= -4.2.x<SUP>‑5</SUP> + -2.x<SUP>-3</SUP>/5<o:p></o:p>
= -8x<SUP>-5</SUP> – 2x<SUP>‑3</SUP>/5<o:p></o:p>
= -8/x<SUP>5</SUP> – 2/5x<SUP>3</SUP><o:p></o:p>

Knowing your index laws is very important.</o:p>
 

Riviet

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d/dx (2/x4 + 1/5x2) = d/dx (2x-4 + 5x-2)
= (-4)(2)x-5 + (-2)(5)x-3
= -8x-5 - 10x-3
= -8/x5 - 10/x3

edit: 1/5x2 was a bit ambiguous. If you meant x2/5, see alexvincent's answer, if you meant 1/(5x2), see my answer.
 
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Getteral09

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Hey can anyone please explain to me this calulus question: 2x(3x^4-x) using the product rule?


Thanks,

From Getteral
 

airie

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Getteral09 said:
Hey can anyone please explain to me this calulus question: 2x(3x^4-x) using the product rule?


Thanks,

From Getteral
This is the product of 2x and 3x4-x. The derivative of 2x is 2, and that of 3x4-x is 12x3-1.

So, by using the product rule, the derivative of the whole expression is 2(3x4-x) + 2x(12x3-1) = 30x4-4x :)
 

Getteral09

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Hep Peeps! can anyone please explain to me this calulus equation using the qoutient rule? Here is the equation: 3x+1/sqrt(x+1)
 

twilight1412

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Getteral09 said:
Hep Peeps! can anyone please explain to me this calulus equation using the qoutient rule? Here is the equation: 3x+1/sqrt(x+1)
quotient rule
u = top
v = bottom
' = derivative

vu' + uv'
-----------
v^2

to get the derivatives you may need to combine rules in your case the chain rule for the bottom ><
 

sando

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let me guess.. you just started yr 12 maths and this is going to be ur homework thread
 

airie

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Or Getteral09 might be in year 10 or lower and just trying to learn more maths than that taught at school :p
 

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