an easy question (1 Viewer)

blackfriday

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its easy, but not for me.

p.121 arnold ex 4.1 q.4(b)

im too stupid to work out how you divide p(x)=x^3-3x^2+4x-2 by (x+i). the example in the book on how to do it was crap.

thanks.
 

withoutaface

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well (x+i)(x-i)=x<sup>2</sup>+1 so what we do is divide by x<sup>2</sup>+1 and then multiply by (x-i) and it should work out.
 

nit

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how about just performing long division with x+i as your divisor, and P(x) as your dividend. :p
 

Arkad

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withoutaface said:
well (x+i)(x-i)=x<sup>2</sup>+1 so what we do is divide by x<sup>2</sup>+1 and then multiply by (x-i) and it should work out.
I don't know about that, what happen if there are remainders? It'll take longer than just doing it the normal long division way with x+i as divident, because you got to divide the remainder by x+i after you've the done the long division with x<sup>2</sup>+1 as divident, I think.

Edit: yeah what nit said.
 
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Slidey

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blackfriday said:
its easy, but not for me.

p.121 arnold ex 4.1 q.4(b)

im too stupid to work out how you divide p(x)=x^3-3x^2+4x-2 by (x+i). the example in the book on how to do it was crap.

thanks.
P(x)=[x^2-(3+i)x+(3+3i)](x+i) + (1-3i)

Do it with synthetic division - much faster and much easier.
 

withoutaface

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nit said:
how about just performing long division with x+i as your divisor, and P(x) as your dividend. :p
I couldn't remember if you could divide by i in 4u maths:p
EDIT: On second thoughts it was a stupid thing to forget.
 

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