1993 HSC Question (1 Viewer)

rama_v

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Hi Guys, I've got a question that I came across in the 1993 exam that I couldn't do. Its question 10.(a) I have attached a copy of the question. I could get part (ii) quite easily but for some reason I cannot get part (iii) - the answer is an exact answer:
x = (sqrt[5] -1)/2

Thanks
 

FinalFantasy

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using the similar triangle u proved, AB/BC= BC\DC=CA\BD
u know AB=1, BC=x
AD=x if u put in the angles properly
hence DC=1-x
BD=x as well if u put in da angles
dat gives u
1/x=x\(1-x) (using AB/BC=BC/DC)
so 1-x=x²
solve that den u should get some stuff
 

velox

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FinalFantasy said:
using the similar triangle u proved, AB/BC= BC\DC=CA\BD
u know AB=1, BC=x
AD=x if u put in the angles properly
hence DC=1-x
BD=x as well if u put in da angles

dat gives u
1/x=x\(1-x) (using AB/BC=BC/DC)
so 1-x=x²
solve that den u should get some stuff
are there any questions you can't do FF :p ? (not specific to this question but in general, you answer every question!)
 

FinalFantasy

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velox said:
are there any questions you can't do FF :p ? (not specific to this question but in general, you answer every question!)
lol i can't do HEAPS, i just don't ask dem here cuz i have my private tutor;)
and the ones i never answer are probability ones and graph ones cuz i am so shit at dem LoL
 

rama_v

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You must spread some Reputation around before giving it to FinalFantasy again.
 

FinalFantasy

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rama_v said:
You must spread some Reputation around before giving it to FinalFantasy again.
lol give it to velox he ans. it first not me
and i dun care about dis reputation thing, but thx anyway haha:p
 

rama_v

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FinalFantasy said:
lol give it to velox he ans. it first not me
and i dun care about dis reputation thing, but thx anyway haha:p
lol, I gave velox a rep too :) thanks velox
 

DeanM

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velox said:
are there any questions you can't do FF :p ? (not specific to this question but in general, you answer every question!)
when you do solve it you get:

(root 5-1)/2
 

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