Class of 2025 (2025 HSC CHAT) (25 Viewers)

Hehehe22

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The days till trials is inversely proportional to the number of messages on this chat If it trials are in 1 day and there are 200 messages today, how many messages would there be if trials were in half a day? (idk if this is correct but I tried so hard)
Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
 

Study to success

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Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
see guys I'm helping u guys study for ur math trials lmao
 

reniiiblaseee

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Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
okayyyy getting that math state rank
 

quokka

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Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
i actually didnt even know that was a math question thats how u know i got an E in year10 math
 

Study to success

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