Recent content by pesila

I'm thinking I'm getting about 110, but given that 119/120 is 100, 95/120 is 95, and 70/120 is 90 (going by rumours and stuff) 110 should be about 98 yeah? 5 marks per aligned mark roughly?

Yeah I put 101-110, but looking for 108-112 hopefully. I thought that test was fun, but I missed some easy marks in questions 8, which was actually easy on the most part. Missed a few in question 6 to my recollection, and missed a selection in the probability. So yeah given a few silly...

You know what? It was a decently easy exam. Poor focus on topics, didn't cover enough of the course and lengthy, but there was nothing too hard there. Even the induction was fairly easy in the end. I didn't get it, only one person from our school did (out of 11) but it's not that hard if you...

Sorry Brisnik, you could do it by subtracting the functions eg y = x^3 -12x - b y' = 3 x^2 - 12 = 0 solve for x = +/- 2 the rest is as I showed before discriminant of y' still doesn't help much though since discriminant = 0 + 12 *3 = 36. Therefore the discriminant is fixed, and...

I stuffed up part ii in the actual exam, which stuffed me up because I thought it was P(losing), so I got a cubic and wasn't willing to try factor theorem for the roots. With the right values for ii and iii it comes out very easily. Just clarifying that

Discriminant applies for a quadratic. This is a cubic, so you could have differentiated to get a quadratic, but that's not doing anything for you. The basic principle here is that a tangent exists where gradients are equal. so we know the gradient of y = 12x + b is 12, so where y = x^3 has...

Um okay well question 3c was 60 and 320 yeah? But question 6 I'm not too sure about all those answers. I just did it again (I probably got most of it wrong in the exam, but this is right I think) i) binomial 4C4 q^4 + 4C3 q^3 p ii) 1 - (4C4 q^4 + 4C3 q^3 p) works to start off since they need...

Yep. 4u was definitely my better exam. I should have aced it. But no, I didn't get an answer for about 7 marks of questions and missed a selection in probability, so looking/hoping for about/above 90% raw in 4u, but in 3u the time was the issue. 4 unit I was finished my first time through...

Time. Not much else to it. Also yeah Priscilla it wasn't very typical of a 3 unit test, which should have a full range of the course in it, and with decent weight on each part of the course. Sure calculus makes up about 40% of the course, but that doesn't mean you put in 60-70% and leave 2...

What can I say? This I guess: In my school I'm topping 3 and 4 unit, never below 90% in any assessment for 3u and an average of about 90% for 4u, and that has to be the hardest exam I've ever done for maths in my life! I was trying to ace it at the start, not that I'd been able to ace an HSC...

Re: Maths EE2 - General thoughts on the exam I thought it was a pretty easy exam. I'm not quite at the standard of Gods like Vafa and Haque, but I think that as long as I didn't make silly mistakes in non-proof questions and my working is coherent enough, I should get a bit above 110. Yeah I...

With reference to choosing 4u over 2u. I think from experience that anyone capable of doing well in 4u, and this is looking at about 70+/120, (not great) but they should be able to get at least 116/120 in 2u incorporating silly mistakes. Keep in mind that people having done 4u tend to get this...

It seems a little weak to just be near the top of the state with 70%. I do my tests under time limits and still get in excess of 80% (96/120). Unless our understanding of top of the state is very different. I am talking about the top group of candidates. Surely you'd get a decent amount...

I'm getting a reasonably consistent 100/120 type raw mark. Does anyone know whereabouts that would get me for a aligned mark? Also, what are other people getting for raw marks and year rankings and schools and such? I figure 100/120 should get comfortably into the 90s, but I'm not too sure...

Okay I tried to post a nice one earlier but it failed, so here goes a little more rushed one. k-i is a factor, so as is k+i by conjugate dealies. p and q are factors. the product equation is (k-i)(k+i)pq = -10. pq(k^2 +1) = -10. Since pq is the product of two integers and k is an integer...