ah so u did the same as me, glad im not alone with my idea lolyeah thats what im thinking so i made a tof equation and suybbed in and everything cancelled nice
ah so u did the same as me, glad im not alone with my idea lolyeah thats what im thinking so i made a tof equation and suybbed in and everything cancelled nice
i got this whole q thankfullythe q16 a) proof though like bro didnt even know the triangle inequality was a 3d proof....
YES, it just worked so perfectly and when it worked i was like surely this is correct and left itah so u did the same as me, glad im not alone with my idea lol
i don't remember what i did but i definitely professionally fucked it upsaid a=4 since v=8 when x=0 and n=2 for memory. but then again couldve stuffed it
probs e z claps for him, he's celebrating rnWhere’s @idkkdi I think we need to know what he thinks of the exam lol.
he got 101/100 obviouslyWhere’s @idkkdi I think we need to know what he thinks of the exam lol.
He's probably doing Ext 3 now.Where’s @idkkdi I think we need to know what he thinks of the exam lol.
he got 101/100 obviously
Probably spent the last 2 hours of the exam taking a nap.He's probably doing Ext 3 now.
Yea I got a=4, and what was the other part of the question again?said a=4 since v=8 when x=0 and n=2 for memory. but then again couldve stuffed it
find what it alternates betweenYea I got a=4, and what was the other part of the question again?
Bruh from what you’ve been saying you’ll get easy band 6, why you stressingfarrrk are you kidding me. another 2 lost.
E4*Bruh from what you’ve been saying you’ll get easy band 6, why you stressing
i ended up with a value of theta 70.53<=θ<90YES, it just worked so perfectly and when it worked i was like surely this is correct and left it
I got a = 5, since the centre of motion is x = 3. What I did was integrate the acceleration function and evaluated the constant using the condition x = 0, v = 8. I got:said a=4 since v=8 when x=0 and n=2 for memory. but then again couldve stuffed it
2k-1, 2kalso how did you do the triangle and hexagon numbers
but those werent initial conditions for memoryI got a = 5, since the centre of motion is x = 3. What I did was integrate the acceleration function and evaluated the constant using the condition x = 0, v = 8. I got:
I then set RHS = 0, and got after dividing through:
in which I said the particle oscillates within the range .
That aside though, god this exam was aids. Never have I hated taking a math exam more in my life. The 2020 kids were playing recruit mode. Truly fearful for Extension 1.
i dont think you had to do all thatFirst part you sub n = (2k-1) and then you get (2k-1)(2k-1+1)/2 = k(2k-1 = 2k^2-k which is h_k
Second Part:
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