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Integration question (1 Viewer)

Thread starter SammyT123
Start date May 8, 2016

S

SammyT123

Active Member

#1

Where did I go so wrong ?
Also yea forgot the +C

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I

InteGrand

Well-Known Member

#2

SammyT123 said:
Where did I go so wrong ?
Also yea forgot the +C

Sent from my iPhone using Tapatalk

$\noindent Since $u=\sqrt{1-x}$, we should have $\mathrm{d}u = -\frac{1}{2\sqrt{1-x}}\text{ d}x$.$

Last edited: May 8, 2016

S

SammyT123

Active Member

#3

InteGrand said:
$\noindent Since $u=\sqrt{1-x}$, we should have $\mathrm{d}u = -\frac{1}{2\sqrt{1-x}}\text{ d}u$.$

Oh yea LOL

Thank you integrand

fluffchuck

Active Member

#4

wheres the dx in the first line? o:

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