Forgot how to solve lol... (1 Viewer)

Drewk · Nov 24, 2012

Hi, need help, forgot how to solve...
2(√3/4)/(1/√2)

Please provide steps and any tips

thanks (sqr root sign is alt and 251 on num pad)

SpiralFlex · Nov 24, 2012

Evaluate*

$2(\frac{\sqrt{3}}{4})(\frac{1}{\sqrt{2}})$

$=\frac{2\sqrt{3}}{4\sqrt{2}}$

"A cute guy told me once by doing nothing you do something"

$=\frac{2\sqrt{3}}{4\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}$

$=\frac{2\sqrt{3}*\sqrt{2}}{8}$

$=\frac{\sqrt{3}*\sqrt{2}}{4}$

$=\frac{\sqrt{6}}{4}$

Drewk · Nov 24, 2012

SpiralFlex said:
Evaluate*

$2(\frac{\sqrt{3}}{4})(\frac{1}{\sqrt{2}})$

$=\frac{2\sqrt{3}}{4\sqrt{2}}$

"A cute guy told me once by doing nothing you do something"

$=\frac{2\sqrt{3}}{4\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}$

$=\frac{2\sqrt{3}*\sqrt{2}}{8}$

$=\frac{\sqrt{3}*\sqrt{2}}{4}$

$=\frac{\sqrt{6}}{4}$

I think u miss interred the question
here is the original Q
Find exact value
http://snag.gy/jVJNs.jpg

SpiralFlex · Nov 24, 2012

Mate, you didn't post that question...

Your second bracket should be, $\frac{\sqrt{3}}{2}$

$=\frac{2\sqrt{3}}{2}*(\frac{1}{\sqrt{2}})$

$=\frac{\sqrt{3}}{\sqrt{2}}$

$=\frac{\sqrt{6}}{2}$

Carrotsticks · Nov 24, 2012

Carrotsticks · Nov 24, 2012

SpiralFlex said:
Mate, you didn't post that question...

He tried to, but forgot that sin60 = root(3)/2. He instead had sin60 = root(3)/4.

Drewk · Nov 24, 2012

Ahhh yes, sorry my fault thanks anyway to both of you

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Forgot how to solve lol... (1 Viewer)

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