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Trial Q (1 Viewer)

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Can someone please do this question and show me their working?


1695717661023.png

I have no idea what this working out means, especially the first line
 

carrotsss

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Luukas.2

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View attachment 39983

Can someone please do this question and show me their working?


View attachment 39984

I have no idea what this working out means, especially the first line
In part (ii), you showed that



so long as a, b, and c are real and positive.



where x, y, and z are suitably chosen positive reals. Putting these into the equation from part (ii):





and thus you get the solution's inequation (1), except in x, y, and z.

Similar substitutions yield the other three inequations, and they sum to give the result required.

The problem with this approach is that the substitutions collectively require a, b, and c to be less than 1.
 
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In part (ii), you showed that



so long as a, b, and c are real and positive.



where x, y, and z are suitably chosen positive reals. Putting these into the equation from part (ii):





and thus you get the solution's inequation (1), except in x, y, and z.

Similar substitutions yield the other three inequations, and they sum to give the result required.

The problem with this approach is that the substitutions collectively require a, b, and c to be less than 1.
why is a, b, c being less than 1 a problem tho cos ii is true for all positive a, b, c
 

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