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MJRey

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No, the original is correct
 

Anaya R

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Nope the original is correct. If we subbed in n=1 into the two equations youll see that the original gives us 1 whereas the the t^(n+1) equation would give us (t^1)+1
 

Lith_30

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Nope the original is correct. If we subbed in n=1 into the two equations youll see that the original gives us 1 whereas the the t^(n+1) equation would give us (t^1)+1
if you subbed n = 1 into the LHS of the original, you would get 1+t, so yeah the original is wrong.
 

chilli 412

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i think to cater to both sides of the argument we should leave it as t^(n+0.5)
 

yanujw

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Definitely wrong. Multiplying both sides by (t-1) shows that the LHS would be a (n+1) degree polynomial, while the RHS would be a n degree polynomial.
original gives us 1
If you sub in 1 the LHS would be (t+1) -> n is the degree of the highest power of t in the LHS.
 
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