plz help with this question (1 Viewer)

[ronaldinho]

x - 3 / |x - 2| = 4

solve for x

 

[pLuvia]

(x-3)/|x-2|=4
If x-2>0
x>2
Then: (x-3)/(x-2)=4
x-3=4x-8
3x=5
x=5/3
If x-2<0
x<2
Then: (x-3)/(x-2)=-4
x-3=-4x+8
5x=11
x=11/5

 

[ronaldinho]

thanks

 

[xlr8-crillz]

(x-3)/|x-2|=4
If x-2>0
x>2
Then: (x-3)/(x-2)=4
x-3=4x-8
3x=5
x=5/3
If x-2<0
x<2
Then: (x-3)/(x-2)=-4
x-3=-4x+8
5x=11
x=11/5

x cant equal 11/5, it doesnt work man try subbing it in. Btw why did u do all this extra crap like "x-2>0". the only possible answer is 5/3.

If i am wrong please tell me my mistake

 

[gamecw]

x cant equal 11/5, it doesnt work man try subbing it in. Btw why did u do all this extra crap like "x-2>0". the only possible answer is 5/3.

If i am wrong please tell me my mistake

note the sign '| |'
|x|=5 --> x= +/- 5

therefore for |x-2|, 'x-2' can be either positive or negative, hence two possible value for x..

his answer looks right to me, hsc: 2008? dont they teach absolute value in year 10?

 

[PC]

Not at my school!

Also worth noting that all this absolute value stuff in not part of the General course either.

 

[xlr8-crillz]

note the sign '| |'
|x|=5 --> x= +/- 5

therefore for |x-2|, 'x-2' can be either positive or negative, hence two possible value for x..

his answer looks right to me, hsc: 2008? dont they teach absolute value in year 10?

woopsies.........but yeh they dont teal "absolute value" in year 10. So i guess thats where i went wrong.

ohh i just had another look, and i didnt actually know wat the | | were at all. Are they like brackets?

 

[pLuvia]

The | | are absolute value signs, for example sqrt{x²}=|x|

 

[Forbidden.]

This question makes me feel shame as an Ext.1er, I won't have quality working out like pLuvia does ...

Mine would simply be multiplying both sides by x-2 then expand ... But I won't get full marks ...