bleakarcher
Active Member
- Joined
- Jul 8, 2011
- Messages
- 1,503
- Gender
- Male
- HSC
- 2013
Last edited:
-
Best of luck to the class of 2025 for their HSC exams. You got this! Let us know your thoughts on the HSC exams here
parametrics (1 Viewer)
- Thread starter bleakarcher
- Start date
so u hav the equation of the tangent at P and at Q. you find the points of intersection and get co-ordinates for R.
well the coordinates of R are:
(3t, 2t^2)
t is your parameter (ur third variable). for the cartesian equation u want a relationship between x and y eliminating t.
so t = x/3
y = 2t^2
therefore y = 2(x/3)^2
y = 2x^2/9
well the coordinates of R are:
(3t, 2t^2)
t is your parameter (ur third variable). for the cartesian equation u want a relationship between x and y eliminating t.
so t = x/3
y = 2t^2
therefore y = 2(x/3)^2
y = 2x^2/9